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6v^2-7v-10=-v^2
We move all terms to the left:
6v^2-7v-10-(-v^2)=0
We get rid of parentheses
6v^2+v^2-7v-10=0
We add all the numbers together, and all the variables
7v^2-7v-10=0
a = 7; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·7·(-10)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{329}}{2*7}=\frac{7-\sqrt{329}}{14} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{329}}{2*7}=\frac{7+\sqrt{329}}{14} $
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